A football punter accelerates a football from rest to a speed of 10 m/s during the time in which his toe is in contact with the ball (about 0.16 s). If the football has a mass of 0.50 kg, what average force does the punter exert on the ball?

force*time= mass*changeofVelocity

solve for force.

To find the average force exerted by the punter on the ball, we can use Newton's second law of motion, which states that force (F) is equal to mass (m) multiplied by acceleration (a). In this case, the acceleration can be calculated using the formula:

a = (vf - vi) / t

Where vf is the final velocity (10 m/s), vi is the initial velocity (0 m/s), and t is the time (0.16 s).

a = (10 m/s - 0 m/s) / 0.16 s
a = 10 m/s / 0.16 s
a = 62.5 m/s²

Now, we can calculate the average force by using the formula:

F = m * a

Where m is the mass of the ball (0.50 kg) and a is the acceleration (62.5 m/s²).

F = 0.50 kg * 62.5 m/s²
F = 31.25 N

Therefore, the punter exerts an average force of 31.25 Newtons on the ball.