Here's some other stuff we never learned in class:
7e-2=47 e=_____ 1/3g=8 g=_____ 5b+1=46 b=______
I don't know how to work them! Please explain as well.
I'll do the first one.
7e-2=47
You need to get the knowns on one side and the unknowns on the other side.
Add 2 to both sides of the equation.
7e = 47 + 2
7e = 49
Divide both sides by 7.
e = 49/7
r = 7
Please follow the above directions and post what you think are the answers for the other two problems. I'll be glad to check them.
So e=7? (I know, e and r are next to eachother!)
Oops -- I have a typo. e = 7
Sorry.
9. 5b+1=46
46+1=47
47/
And then I get stuck. All the problems are different so do the same rules apply?
Subtract 1 from both sides.
5b = 45
46-1=45
45/5=9
b=9?
P.S My great grandma got home safely
You're right. And I'm glad your great grandma is o.k. :-)
What about 1/3g=8?
1/3g=8
g = 8 / (1/3)
g = 8 * (3/1)
g = 24
To solve these equations, we need to isolate the variable on one side of the equation. Let's work through each equation step by step:
1) 7e - 2 = 47
To isolate e, we can start by moving the constant term (-2) to the other side of the equation by adding 2 to both sides:
7e - 2 + 2 = 47 + 2
This simplifies to:
7e = 49
Next, to solve for e, we need to get rid of the coefficient 7. We can do this by dividing both sides of the equation by 7:
(7e) / 7 = 49 / 7
Which gives us:
e = 7
So, in this equation, e is equal to 7.
2) 1/3g = 8
To isolate g, we can start by multiplying both sides of the equation by the reciprocal of 1/3, which is 3/1 or simply 3:
(1/3g) * 3 = 8 * 3
This simplifies to:
g = 24
Therefore, g is equal to 24.
3) 5b + 1 = 46
To isolate b, we can start by moving the constant term (1) to the other side of the equation by subtracting 1 from both sides:
5b + 1 - 1 = 46 - 1
This simplifies to:
5b = 45
Next, to solve for b, we need to get rid of the coefficient 5. We can do this by dividing both sides of the equation by 5:
(5b) / 5 = 45 / 5
Which gives us:
b = 9
Therefore, b is equal to 9.
To summarize the solutions:
e = 7
g = 24
b = 9