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a horizontal wire is stretched between two vertical poles. when a 12.0-N weight is suspended at its center, the wire sags until the angle between its halves is 110 degrees. what are the forces exerted by each half of the wire in supporting the weight?

i don't really get the question..and how to solve it

1) you have symettry, so you can work just one side.
2) draw a triangle, angles 55, 90(at top), and 35. This represents the wire sag on one side and the horizontal across the top.

It is supporting 12/2 N down. Tension/6 = sin 35. Check that. Solve for tension

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