A 5kg box on a horizontal plane has a coefficient of kinetic energy of 0.2. The object is pulled on horizontally with a rope at 2 m/s^2. With 9.8m/s^2 gravitational force, what is the tension on the rope?
To find the tension on the rope, we need to consider the forces acting on the box. There are two main forces at play here: the force pulling the box horizontally and the force due to gravity.
First, let's calculate the force due to gravity acting on the box. The force due to gravity is given by the formula:
Force due to gravity = mass * acceleration due to gravity
Plugging in the values, we have:
Force due to gravity = 5 kg * 9.8 m/s^2 (acceleration due to gravity)
Force due to gravity = 49 N
Next, let's calculate the force pulling the box horizontally. The formula for force is given by:
Force = mass * acceleration
Plugging in the values, we have:
Force = 5 kg * 2 m/s^2 (horizontal acceleration)
Force = 10 N
Now, the tension on the rope is equal to the sum of these two forces. Since the box is moving horizontally, the force required to overcome the friction between the box and the surface is equal to the force pulling the box horizontally.
Tension on the rope = Force due to gravity + Force
Tension on the rope = 49 N + 10 N
Tension on the rope = 59 N
Therefore, the tension on the rope is 59 N.