Algebra

I have the answer, but don't know the procedure.

The question is:

Find the values of C and D if
c/(x-2) + D/(x+1) = 6x/(x^2-x-2)

The answers are: C= 4, D=2

HERE IS MY WORK:
Well, I know that we can add the left side and the denominators become the same. So, the new equations becomes:

c(x+1)+ D(x-2) = 6x

but, how do you go from here to find the values of c and d?

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  1. C/(x-2) + D/(x+1) = 6x/(x-2)(x+1)
    Rewrite the terms on the left so that they have the same denominator as the term on the right.
    C(x+1) + D(x-2)/[(x-2)(x+1)] =
    6x/(x-2)(x+1)

    Cx + C + Dx -2D = 6x

    This can only be true if C+D= 6 and C-2D = 0
    Solve those two equations to get C and D

    This is called the method of partial fractions

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