Calculate the percent composition of calcium acetate.
To calculate the percent composition of calcium acetate, you need to know the formula for calcium acetate and the molar masses of each individual element present in the compound.
The formula for calcium acetate is Ca(C2H3O2)2.
To calculate the percent composition, follow these steps:
Step 1: Determine the molar mass of calcium acetate.
The molar mass of calcium (Ca) is 40.08 g/mol.
The molar mass of carbon (C) is 12.01 g/mol.
The molar mass of hydrogen (H) is 1.01 g/mol.
The molar mass of oxygen (O) is 16.00 g/mol.
Considering the formula Ca(C2H3O2)2, multiply the molar masses of each individual element by their respective subscripts and sum them up:
Molar mass of calcium acetate = (1 × molar mass of Ca) + (2 × molar mass of C) + (3 × molar mass of H) + (2 × molar mass of O)
Step 2: Calculate the percent composition of each element.
Percent composition of calcium (Ca) = (mass of Ca / molar mass of calcium acetate) × 100%
Percent composition of carbon (C) = (mass of C / molar mass of calcium acetate) × 100%
Percent composition of hydrogen (H) = (mass of H / molar mass of calcium acetate) × 100%
Percent composition of oxygen (O) = (mass of O / molar mass of calcium acetate) × 100%
Note: The mass of each element can be calculated using experimental data or by assuming a certain quantity of calcium acetate.
Step 3: Add up the percent compositions of all elements to get the total percent composition of calcium acetate.
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To calculate the percent composition of calcium acetate (Ca(CH3COO)2), you need to determine the molar mass of each element in the compound.
1. Calcium (Ca):
- Atomic mass of calcium (Ca) = 40.08 g/mol
2. Carbon (C):
- Atomic mass of carbon (C) = 12.01 g/mol
- Since there are two carbon atoms in calcium acetate, the total mass of carbon = 2 * 12.01 g/mol = 24.02 g/mol
3. Hydrogen (H):
- Atomic mass of hydrogen (H) = 1.01 g/mol
- Since there are four hydrogen atoms in calcium acetate, the total mass of hydrogen = 4 * 1.01 g/mol = 4.04 g/mol
4. Oxygen (O):
- Atomic mass of oxygen (O) = 16.00 g/mol
- Since there has four oxygen atoms in calcium acetate, the total mass of oxygen = 4 * 16.00 g/mol = 64.00 g/mol
Now, let's calculate the total molar mass of calcium acetate:
Total molar mass = mass of calcium + mass of carbon + mass of hydrogen + mass of oxygen
= 40.08 g/mol + 24.02 g/mol + 4.04 g/mol + 64.00 g/mol
= 132.14 g/mol
To find the percent composition of calcium acetate:
1. Calcium:
Percent composition of calcium = (mass of calcium / total molar mass) x 100%
= (40.08 g/mol / 132.14 g/mol) x 100%
≈ 30.32%
2. Carbon:
Percent composition of carbon = (mass of carbon / total molar mass) x 100%
= (24.02 g/mol / 132.14 g/mol) x 100%
≈ 18.16%
3. Hydrogen:
Percent composition of hydrogen = (mass of hydrogen / total molar mass) x 100%
= (4.04 g/mol / 132.14 g/mol) x 100%
≈ 3.06%
4. Oxygen:
Percent composition of oxygen = (mass of oxygen / total molar mass) x 100%
= (64.00 g/mol / 132.14 g/mol) x 100%
≈ 48.45%
Therefore, the percent composition of calcium acetate is approximately:
- Calcium (Ca): 30.32%
- Carbon (C): 18.16%
- Hydrogen (H): 3.06%
- Oxygen (O): 48.45%
Ca(C2H3O2).
%Ca = [(mass Ca)/(mass calcium acetate)]*100
%H = [(mass H)/(mass calcium acetate)]*100
%O = [(mass O)/(mass calcium acetate)]*100
%C = [(mass C)/(mass calcium acetate)]
*100
Use atomic mass for mass of the atoms multiplied by the number of atoms in calcium acetate.
Use molar mass of calcium acetate for its mass.