from what height should you drop your physics textbook so that it takes 0.2 seconds for it to fall? ftom what height would you drop a baseball so it takes 0.2 seconds for it to fall?
please helpppp
Drag out your standard formula!
s = 1/2 at^2
s = 16(.2)^2
s = 16*.04
s = 0.64 feet
To determine the height from which you should drop an object so that it takes a specific time to fall, we can use the equation for free fall:
h = (1/2) * g * t^2,
where:
h is the height (in meters or feet),
g is the acceleration due to gravity (9.8 m/s^2 or 32.2 ft/s^2 on Earth),
t is the time taken to fall (in seconds).
Let's solve this equation for the textbook first. Given that the time it takes for the textbook to fall is 0.2 seconds, we will substitute the values into the equation:
h = (1/2) * g * t^2
h = (1/2) * (32.2 ft/s^2) * (0.2 s)^2
Calculating this, we get:
h ≈ 0.6464 ft
Therefore, you should drop your physics textbook from a height of approximately 0.6464 feet, so that it takes 0.2 seconds to fall.
Now let's calculate the height from which you should drop a baseball. By using the same equation and time (0.2 seconds), we can determine the height:
h = (1/2) * g * t^2
h = (1/2) * (32.2 ft/s^2) * (0.2 s)^2
Calculating this, we get:
h ≈ 0.6464 ft
Hence, you should drop the baseball from a height of approximately 0.6464 feet, so that it takes 0.2 seconds to fall.