A constant net force of 385 N is applied upward to a stone that weighs 28 N. The upward force is applied through a distance of 2.0 m, and the stone is then released. To what height, from the point of release, will the stone rise?

what formula(s) do i use?

This question was answered elsewhere. If you assume the net force includes the weight, multiply 385 N by 2.0 m to get the kinetic energy when it is released. Call that K.E.= 770 J

Then use K.E = M g h = W h
to get the additional height H that it rises after release. W is the weight in Newtons.
In one step,
h = (net force)*(2.0 m)/W

To calculate the height to which the stone will rise, you can make use of the principle of work done and the conservation of energy.

First, let's calculate the work done by the net force on the stone as it moves upward through a distance of 2.0 m. The work done (W) is given by the formula:

W = force × distance

In this case, the force is the constant net force of 385 N, and the distance is 2.0 m. Therefore, the work done on the stone is:

W = 385 N × 2.0 m = 770 J

According to the principle of work done, this work done on the stone will be converted into the potential energy of the stone when it reaches its maximum height.

The potential energy (PE) can be calculated using the formula:

PE = mass × gravitational acceleration × height

However, in this case, we need to solve for the height. Rearranging the formula, we have:

height = PE / (mass × gravitational acceleration)

The mass of the stone is 28 N (weight), and the gravitational acceleration can be taken as approximately 9.8 m/s².

Therefore, the height can be calculated as:

height = 770 J / (28 N × 9.8 m/s²)

Simplifying the equation, we get:

height ≈ 2.74 m

So, the height to which the stone will rise from the point of release is approximately 2.74 meters.