Calculus

Find dy/dx by implicit differentiation:
x^2-2xy+y^3 = c

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  1. x² - 2xy + y³ = c

    2x - 2y - 2xy' + 3y² y' = 0

    2(x-y) + y'(3y²-2x) = 0

    y' = 2(y-x)/(3y²-2x)

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