Questions LLC
Login
or
Sign Up
Ask a New Question
Math
Calculus
Find the Domain of f(x)=sqrt(x^3-4x+1)
1 answer
The domain is the values of x where f(x) is defined. The square root requires the radicand to be ≥ 0.
So, x^3 - 4x + 1 ≥ 0
x ∈ [-2.1,0.24] ∪ [1.83,+∞)
You can
ask a new question
or
answer this question
.
Related Questions
1. The length of the hypotenuse of a 30-60-90 triangle is 7. Find the perimeter.
A) 7/2+21/2 sqrt 3 B) 21+7 sqrt 3 C) 7+21 sqrt 3
Find the unit vector in the direction of u=(-3,2). Write your answer as a linear combination of the standard unit vectors i and
A square root function has a domain of x greater than or equal to -4 and range of y grreater than or equal to 2. Which of the
1. Evaluate tan[sin^-1(a)].
a. [sqrt(1-a^2)]/1-a^2 b. [sqrt(1-a^2)]/a c. sqrt(1-a^2) d. {a[sqrt(1-a^2)]}/1-a^2 I do not know the
Evaluate sqrt7x (sqrt x-7 sqrt7) Show your work.
sqrt(7)*sqrt(x)-sqrt(7)*7*sqrt(7) sqrt(7*x)-7*sqrt(7*7) sqrt(7x)-7*sqrt(7^2)
Find the domain of the vector function r(t)= sqrt(4 - t ^ 2) i + sqrt(t) j - 2 / (sqrt(1 + t)) k.
answer in interval notation
f(x)=-4x-2 & g(x)=5x-6. Find (f*g) and state domain.
f(x)-x^2-1 what is the equation for f^-1(x)? f(x)=3x+2, find f(f^-1(14)).
1)Find the exact value of cos 105 by using a half-angle formula.
A)sqrt 2 - sqrt 3 /2 B)-sqrt 2 - sqrt 3 /2 C)-sqrt 2 + sqrt 3 /2
f(x)= 4-x^2 and g(x)= sqrt (x)
find the implied domain of fg(x) fg(x)= f(sqrt(x)) fg(x)= 4-(sqrt(x))^2 fg(x)=4-(sqrt x)(sqrt x)
find the domain of the real valued function;
f(x) = sqrt(5 - (sqrtx)) my solution: 5 - (sqrt x) >=0 -(sqrt x) >= -5 (sqrt x) <= 5
