Two children on racing bikes start from the same reference point. Child A travels 5.0m/s{right} and child B travels 4.5m/s{right}. How much farther from the point of origin is child A than child B after 5.os?
pls I really really need help. I do not understand it and I do not knoe
w the formula to use to solve it. pls help
relative distance=relative velocity*time
= .5*5=2.5m
To solve this problem, we first need to understand the concept of relative motion.
Child A is moving to the right with a velocity of 5.0 m/s, and Child B is also moving to the right with a velocity of 4.5 m/s. The difference between their velocities is 5.0 m/s - 4.5 m/s = 0.5 m/s.
Since both children started from the same reference point, we can consider this point as the origin. Now we need to find how much farther Child A is from the origin compared to Child B after 5.0 seconds.
To calculate the distance traveled by each child, we multiply their velocities by the time. The distance formula is:
Distance = Velocity × Time
For Child A:
Distance_A = Velocity_A × Time = 5.0 m/s × 5.0 s = 25 m
For Child B:
Distance_B = Velocity_B × Time = 4.5 m/s × 5.0 s = 22.5 m
Now, to find the difference in distances between Child A and Child B:
Difference = Distance_A - Distance_B = 25 m - 22.5 m = 2.5 m
Therefore, Child A is 2.5 meters farther from the point of origin compared to Child B after 5.0 seconds.