Give the mass in grams of diphosphorus pentoxide that contains 2.0 x 10^(24) oxygen atoms.
P2O5
2E24/6.022E23 = moles O atoms.
moles O atoms/5 = moles P2O5 molecules.
moles P2O5 = grams P2O5/molar mass P2O5. Solve for grams P2O5.
To find the mass of diphosphorus pentoxide (P2O5) that contains a given number of oxygen atoms, you need to use the molar ratio and the atomic masses of the elements involved.
Step 1: Find the molar mass of P2O5.
The molar mass of P2O5 can be calculated by summing the atomic masses of its constituent elements. The atomic masses are found on the periodic table.
Phosphorus (P): Atomic mass = 30.97 g/mol
Oxygen (O): Atomic mass = 16.00 g/mol
Molar mass of P2O5 = (2 × atomic mass of P) + (5 × atomic mass of O)
= (2 × 30.97 g/mol) + (5 × 16.00 g/mol)
= 62.00 g/mol + 80.00 g/mol
= 142.00 g/mol
Step 2: Calculate the number of moles of oxygen atoms.
To determine the number of moles, you can use Avogadro's number, which states that 1 mole of any substance contains 6.022 × 10^23 particles.
Number of moles of oxygen atoms = (2.0 × 10^24) / (6.022 × 10^23)
= 3.32 moles
Step 3: Convert moles of oxygen to moles of diphosphorus pentoxide.
The molar ratio is used to convert between different chemical species. From the balanced chemical formula of diphosphorus pentoxide (P2O5), we can determine the mole ratio between oxygen atoms and P2O5.
In P2O5, there are 5 oxygen atoms for every 1 P2O5 molecule.
Number of moles of diphosphorus pentoxide = Number of moles of oxygen atoms / Molar ratio
= 3.32 moles / 5
= 0.664 moles
Step 4: Find the mass of diphosphorus pentoxide.
Mass = Number of moles × Molar mass
= 0.664 moles × 142.00 g/mol
= 94.448 g
So, the mass of diphosphorus pentoxide that contains 2.0 × 10^24 oxygen atoms is approximately 94.448 grams.