To add 32 + 56, Juanita first added 30 + 50. What steps does she still need to do to find the sum? What is Juanita's sum?
2+6 = 8
80+8 = 88
I do not now.
To add 32+56, Juanita first added 30+50. What two steps does she still need to do to find the sum? What is Juanita's sum?
HOW CAN STEVE ADD 48+34 BY MAKING A TEN? What is the sum.
To find the sum of 32 + 56, Juanita initially simplified the problem by adding 30 + 50. This step involves adding the tens digits (3 + 5) and the ones digits (0 + 0) separately to get the partial sum of 80.
After completing this step, Juanita still needs to add the partial sum of 80 to the remaining digits of the numbers (2 and 6) to determine the final sum.
Therefore, the remaining step for Juanita is to add 80 + 2 + 6. When Juanita performs this addition, she will get a sum of 88.
Therefore, Juanita's sum is 88.