What force must be exerted on block A in order for block b not to fall. The coefficient of static friction between block A and B is 0.55, and the horizontal surface is frictionless.
A= 100kg and B=10kg
A is on the horizontal surface and B is attached to A.
To determine the force required on block A in order for block B not to fall, we can analyze the forces acting on the system.
First, let's consider the gravitational forces acting on the blocks. Block A with a mass of 100 kg experiences a downward force due to gravity, which is given by its weight:
Force of gravity on block A = mass of block A * acceleration due to gravity
= 100 kg * 9.8 m/s^2
= 980 N
Block B with a mass of 10 kg also experiences a downward force due to gravity:
Force of gravity on block B = mass of block B * acceleration due to gravity
= 10 kg * 9.8 m/s^2
= 98 N
Since the two blocks are connected, they will exert forces on each other. The force exerted on block A by block B is equal in magnitude and opposite in direction to the force exerted on block B by block A. We'll denote this force as the frictional force between block A and block B.
The maximum static frictional force can be calculated using the coefficient of static friction. The coefficient of static friction (μ) is given as 0.55. The maximum static frictional force (F_max) can be calculated using the following equation:
F_max = μ * (Force of normal reaction)
The force of normal reaction (Force of contact) is the force exerted on block A by the surface, which is equal to the weight of block A:
Force of normal reaction = weight of block A
= Force of gravity on block A
= 980 N
Now, let's calculate the maximum static frictional force:
F_max = μ * (Force of normal reaction)
= 0.55 * 980 N
= 539 N
To prevent block B from falling, the force exerted on block A should be equal to or greater than the maximum static frictional force. Therefore, the force required on block A is 539 N or more.