How much heat is emitted when 4.55 of water condenses at 25 ? The heat of vaporization of water at 25 is 44.0
To calculate the amount of heat emitted when water condenses, you can use the equation:
Q = m * ΔH
Where:
Q is the heat energy emitted (in joules),
m is the mass of water (in grams), and
ΔH is the heat of vaporization (in joules per gram).
First, convert the given mass of water from 4.55 g to kilograms:
m = 4.55 g / 1000 = 0.00455 kg
Now, substitute the values into the equation:
Q = 0.00455 kg * 44.0 J/g
To get the final answer, multiply the mass of water by the heat of vaporization:
Q = 0.00455 kg * 44.0 J/g = 0.2002 J
Therefore, when 4.55 g of water condenses at 25°C, approximately 0.2002 Joules of heat energy is emitted.