Change the exponentioanl expression to an equivalent expression involving a logarithm. e^-1/3 = 9t
Somebody help PLease!
take the natural log (ln ) of each side.
-1/3=ln(9t)
I can't believe it's that simple, I have been going crazy! Thank you!
To change the exponential expression e^(-1/3) = 9t to an equivalent expression involving a logarithm, you can use the natural logarithm function, denoted as ln(x).
The basic idea is to take the logarithm of both sides of the equation.
So, start by taking the natural logarithm of both sides:
ln(e^(-1/3)) = ln(9t)
Now, since the natural logarithm (√) and the exponential function (e^x) are inverse operations, they cancel each other out, leaving us with:
-1/3 = ln(9t)
Hence, the equivalent expression involving a logarithm is -1/3 = ln(9t).