A bullet is fired with a speed of 450 m/s through a board 20cm thick. If the bullet is subject to a large deceleration of magnitude 10^6m/s^2, will the bullet be able to emerge from the other side of the board.?
To determine whether the bullet will be able to emerge from the other side of the board, we can use the equation of motion:
v^2 = u^2 + 2as
Where:
v is the final velocity of the bullet (0 m/s, since it will stop)
u is the initial velocity of the bullet (450 m/s)
a is the deceleration (10^6 m/s^2)
s is the distance traveled through the board (20 cm = 0.2 m)
We need to rearrange the equation to solve for the final velocity (v):
v^2 = u^2 + 2as
0^2 = 450^2 + 2 * 10^6 * 0.2
Simplifying the equation:
0 = 202,500 + 400,000
0 ≠ 602,500
Since the equation does not balance, it means that the bullet will not be able to emerge from the other side of the board.