Confused! Please help!!
Assume an organic compound has a partition coefficient between water and diethyl ether equal to 6.63. If there are initially 9.05 grams of the compound dissolved in 80.0 mL of water, how many grams will remain in the aqueous layer after extraction with one 30.0 mL portion of ether?
To determine how many grams of the compound will remain in the aqueous layer after extraction, we need to understand the concept of partition coefficient and the process of extraction.
The partition coefficient (P) is a measure of how a compound distributes itself between two immiscible (unmixable) solvents. In this case, the partition coefficient between water and diethyl ether is given as 6.63.
Extraction is a process that separates a compound from a mixture using two immiscible solvents. In this case, water and diethyl ether are the solvents.
To solve this problem, we can follow these steps:
Step 1: Calculate the amount of compound initially dissolved in the aqueous layer.
Given: mass of compound = 9.05 grams
volume of water = 80.0 mL
Step 2: Calculate the amount of compound extracted into the diethyl ether layer.
To do this, we need to use the partition coefficient (P):
Amount extracted = partition coefficient × amount in aqueous layer
Step 3: Calculate the amount remaining in the aqueous layer after extraction.
Amount remaining = initial amount - amount extracted
Let's calculate the amount of compound extracted into the diethyl ether layer:
Amount extracted = partition coefficient × amount in aqueous layer
= 6.63 × 9.05 grams
≈ 59.92 grams
Now, let's calculate the amount of compound remaining in the aqueous layer:
Amount remaining = initial amount - amount extracted
= 9.05 grams - 59.92 grams
≈ -50.87 grams
Since the result is negative, it means there will be no compound remaining in the aqueous layer after extraction with the diethyl ether.
Therefore, no grams will remain in the aqueous layer after extraction with one 30.0 mL portion of ether.