What is the net ionic equation for the reaction
Cu(s) + 2 Ag (NO3)2(aq) --- Cu(NO3)2(aq) + 2AG(s)
Cu(s) + 2Ag^+(aq) ==> Cu^2+(aq) + 2Ag(s)
You see the nitrate ion (2 of them) on each side; they don't enter into the reaction.
ni(NO3)2 (aq) +NaOH(aq)=NI(OH)2 (s) +NaNo3(aq)
To find the net ionic equation for a reaction, you need to first write the balanced complete ionic equation and then remove the spectator ions to get the net ionic equation.
Step 1: Write the balanced complete ionic equation.
The given balanced equation is: Cu(s) + 2 Ag(NO3)2(aq) → Cu(NO3)2(aq) + 2 Ag(s)
Since copper (Cu) is a solid (s), it does not dissociate into ions in the solution. Therefore, it remains unchanged in aqueous form in the reaction.
The silver nitrate (AgNO3) dissociates into its respective ions:
Cu(s) + 2 Ag+(aq) + 2 NO3-(aq) → Cu(NO3)2(aq) + 2 Ag(s)
Step 2: Remove the spectator ions.
Spectator ions are the ions that appear on both sides of the equation unchanged. In this case, the Cu2+ and the NO3- ions are spectators because they are present on both sides of the equation.
Cu(s) + 2 Ag+(aq) + 2 NO3-(aq) → Cu(NO3)2(aq) + 2 Ag(s)
The spectator ions can be removed to obtain the net ionic equation.
Step 3: Write the net ionic equation.
The net ionic equation is obtained by removing the spectator ions, which gives:
Cu(s) + 2 Ag+(aq) → Cu(NO3)2(aq) + 2 Ag(s)
Therefore, the net ionic equation for the given reaction is Cu(s) + 2 Ag+(aq) → Cu(NO3)2(aq) + 2 Ag(s).