C4H10O(l) + O2(g) --- CO(g) + H2O(g)
When I balanced it I got this
C4H10O(I) + 4O2(g) --- 4CO(g) + 5H2O
Am I correct
Yes; however, you need not ask if you are correct. You count atoms on the left and see if the same number is on the right. If so it balances; if not, it doesn't.
I see 4C atoms on each side.
I see 10 H atoms on each side.
I see 9 O atoms on each side.
Balanced.
Yes, you are correct. The balanced equation for the reaction is:
C4H10O(l) + 4O2(g) → 4CO(g) + 5H2O(g)
Yes, you are correct. The balanced equation you provided is correct.
To balance a chemical equation, you need to ensure that the number of atoms of each element is the same on both sides of the equation.
In this case, you have the reactant C4H10O (a compound called butanol) and the products CO (carbon monoxide) and H2O (water).
To balance the carbon atoms, you have 4 carbon atoms on the left side (in C4H10O) and 4 carbon atoms on the right side (in 4CO).
To balance the hydrogen atoms, you have 10 hydrogen atoms in C4H10O on the left side, and 5 hydrogen atoms in H2O on the right side. Therefore, you need to add a coefficient of 5 in front of H2O to balance the hydrogen atoms.
To balance the oxygen atoms, you have 1 oxygen atom in C4H10O on the left side, and 4 oxygen atoms in O2 on the right side. Therefore, you need to multiply the coefficient of O2 by 4 to have a total of 4 oxygen atoms on the left side.
Balancing the equation, you get:
C4H10O(l) + 4O2(g) → 4CO(g) + 5H2O(g)
So, your balanced equation is correct.