Calculate the number of molecules in 3.11mol of CCL4

this is what I'm doing
I got the molecular weight of CCL4 which is 181.88
Then I set it up like this
3.11 mol CCL4/ 181.88 mol CCL4 x 6.022E23 = 1.03E22
Am I right

Yes, you are on the right track. To calculate the number of molecules in 3.11 mol of CCl4, you can use the Avogadro's number and the molecular weight of CCl4.

First, you correctly determined the molecular weight of CCl4 as 181.88 g/mol.

Then, you set up the calculation as follows:
3.11 mol CCl4 / 181.88 g CCl4/mol x 6.022 x 10^23 molecules/mol

By multiplying these values, you obtain the number of molecules in 3.11 mol of CCl4.

Calculating that, you get:
(3.11 mol CCl4 / 181.88 g CCl4/mol) x 6.022 x 10^23 molecules/mol = 1.03 x 10^23 molecules

So, you are correct. There are approximately 1.03 x 10^23 molecules in 3.11 mol of CCl4.