(3t+1)/5=(t+7)/10+(t-5)/10
I solved this question through the linear equation simplification timing both sides by the least common denominator. 5
Once I did the the result was >
3t+1= 2t+14+2t-10
T= 3
However the real answer is t=0
Where am I going wrong?
How am I supposed to simplify this equation?
(3t+1)/5=(t+7)/10+(t-5)/10
multiply both sides by 10
2(3t+1)=t+7+t-5
6t+2=2t+2
subtract two from each side
6t=2t
subtract 2t from each side
4t=0
t=0
multiply each term by 10 , not 5
2(3t+1) = t+7 + t-5
6t + 2 = 2t + 2
4t = 0
t = 0
Hm, so I am supposed to multiple each side by the largest common factor. Correct
If you have an equation with fractions, multiply each term by the lowest common denominator of those fractions.
Which in this case is 10?
Could you please give me a complex solution like this, so I can quickly reassure my self>
try
(x+4)/2 + 5/3 = (2x-1)/5
you should get x = -116/3
(obviously I did not "plan" the equation to come out nicely, just wrote down some numbers)