If the pressure on a balloon were quadrupled what would happen to the balloons volume?
P1V1 = P2V2
Since no initial P is given, just make up a value, then quadruple it for P2.
So just any random number I can quadruple it to?
right. Why not go the easy route and make P1 = 1 and P2 = 4.
Then you need to make V1 = 4 and solve for V2.
Another way to do it is use
P1V1 = P2V2 and set P2 = 4P1
So P1V1 = 4P1V2 and solve for
V1/V2 = 4P1/P1
So V1/V2 = 1P1/4P1, the P1 cancels to obtain
V1/V2 = 4
V1 = 4V2 or
V2 = (V1/4) = 1/4 V1
To determine what would happen to the balloon's volume if the pressure were quadrupled, we need to understand the relationship between pressure and volume described by Boyle's Law. According to Boyle's Law, at a constant temperature, the pressure and volume of a gas are inversely proportional to each other.
In other words, if we increase the pressure on the balloon, the volume will decrease, and if we decrease the pressure, the volume will increase. This means that when the pressure is quadrupled, the volume of the balloon will decrease.
To understand this conceptually, imagine squeezing a balloon. As you squeeze it, the pressure inside the balloon increases, causing the volume to shrink. Similarly, if you release the pressure, the balloon expands.
In summary, when the pressure on a balloon is quadrupled, its volume will decrease.