I AM A FOUR-DIGIT EVEN NUMBER. THE SUM OF MY DIGITS IS 15. THE ONES DIGIT IS ONE MORE THAN TENS DIGIT,WICH IS ONE MORE THAN THAN THE THOUSANDS DIGIT. THE HUNDREDS DIGIT IS THE SUM OF THE ONES AND THOUSANDS DIGITS. THE TENS DIGIT IS 3. WHAT AM I ?

Let ones=x

tens=y
hundreds=z
thousands=a

a+x+y+z=15
x=1+y
y=a+1
z=x+a
y=3

x=1+(3)
x=4

(3)=a+1
a=2

z=(4)+(2)
z=6

2634

To solve this problem, let's break it down and analyze the given information step by step:

1. The tens digit is 3.
2. The sum of all the digits is 15.
3. The ones digit is one more than the tens digit.
4. The tens digit is one more than the thousands digit.
5. The hundreds digit is the sum of the ones and thousands digits.

From the information provided, we can start solving the problem:

Step 1: The tens digit is 3.
From this information, we know that the tens digit is 3.

Step 2: The sum of all the digits is 15.
Given that the sum of all the digits is 15, we can write an equation:
thousands digit + hundreds digit + tens digit + ones digit = 15.

Step 3: The ones digit is one more than the tens digit.
Since the tens digit is 3, the ones digit is one more than that, which means the ones digit is 4.

Step 4: The tens digit is one more than the thousands digit.
Based on the information given, the thousands digit must be 2, as it is one less than the tens digit.

Step 5: The hundreds digit is the sum of the ones and thousands digits.
Given that the thousands digit is 2 and the ones digit is 4, we can calculate the hundreds digit as the sum of these two digits which is 6.

Therefore, combining all the digits together, the number that satisfies all the given conditions is 2634.