Jan is on year younger than her brother Bill and on year older then her sister Sue. The sun of the three children ages is 57. How old is each child.k
Let x = Jan's age, then x+1 = Bill's and x-1 = Sue's.
x + (x-1) + (x+1) = 57
Solve for x.
To solve this problem, we can start by assigning variables to the ages of Jan, Bill, and Sue. Let's say Jan's age is J, Bill's age is B, and Sue's age is S.
Based on the information given in the question, we can create three equations:
1. Jan is one year younger than Bill: J = B - 1
2. Jan is one year older than Sue: J = S + 1
3. The sum of their ages is 57: J + B + S = 57
Now, we can use these equations to solve for the ages of the children.
Substituting the first equation into the second equation, we get:
B - 1 = S + 1
Simplifying, we find:
B = S + 2
Substituting these values into the third equation, we have:
J + B + S = 57
(J + (S + 2) + S = 57
2J + 2S + 2 = 57
2J + 2S = 55
Now, we have a system of two equations with two variables (J and S):
J = B - 1
2J + 2S = 55
We can solve this system of equations to find the values of J and S.
By substituting B = S + 2 from the first equation into the second equation, we get:
2J + 2(S + 2) = 55
2J + 2S + 4 = 55
2J + 2S = 51
Next, subtracting the second equation (2J + 2S = 51) from the third equation (2J + 2S = 55), we find:
2J + 2S - (2J + 2S) = 55 - 51
0 = 4
This equation tells us that there is no solution for J and S. Therefore, something is incorrect in the given information or calculations.
Please review the problem statement and check for any mistakes or missing information.