How high will a 1.60-{\rm kg} rock go if thrown straight up by someone who does 75.0 J of work on it? Neglect air resistance.
F = (m)(a)
F = (1.6 kg)(9.0 N/kg)= 15.58 N
W = (F)(S) so, F= W/S
75 J / 15.68 N = 4.78 m
F = (1.6 kg)(9.0 N/kg)= 15.58 N
W = (F)(S) so, F= W/S
75 J / 15.68 N = 4.78 m