Suppose that X liters of 38% acid solution are mixed with y liters of a 42% solution to obtain 100L of a 39% solution. One equation in a system for solving this problem is x+y=100. Which one of the following is the other equation? A. 42x+38y=0.39*100 B 0.38x+0.42y=0.39*100 C. 0.42x+0.38y=0.39*100 D. 38x+42y=39
Looks like B to me. A and C both have 42x, but we know x is 38% solution.
Choice B says that the total acid in x liters + y liters is 39% of the resulting 100 Liters.
To solve this problem, we need to set up a system of equations based on the given information.
Let's start by setting up the first equation.
The first equation given is:
x + y = 100
This equation represents the total amount of solution we want to obtain, which is 100 liters.
Now, we need to find the second equation.
We know that the total amount of acid in the final solution must be equal to the sum of the acid in the two initial solutions.
The acid in the 38% solution is 38% of x liters, which can be written as:
0.38x
The acid in the 42% solution is 42% of y liters, which can be written as:
0.42y
The total acid in the final solution is 39% of 100 liters, which can be written as:
0.39 * 100
Thus, the second equation is:
0.38x + 0.42y = 0.39 * 100
Therefore, the correct answer is B. 0.38x + 0.42y = 0.39 * 100