1. On final examination in Business Law, the mean was 68 and the standard deviation was 12. Determine the standard scores of students receiving marks of 50?
Are you looking for the z score?
If so,
x-x bar (mean)/sd
50-68 / 12
-1.5
This particular datum is 1.5 sd's below the mean.
Yes i'm looking for the z score.
Thank you so much.
To determine the standard score (also known as z-score) for a student receiving a mark of 50, you can use the formula:
z = (x - μ) / σ
where:
- z is the standard score
- x is the student's mark (in this case, 50)
- μ is the mean of the exam scores (in this case, 68)
- σ is the standard deviation of the exam scores (in this case, 12)
Substituting the given values into the formula:
z = (50 - 68) / 12
Calculating the equation:
z = -18 / 12 = -1.5
Therefore, the standard score for a student receiving a mark of 50 is -1.5.