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Math
how to divide 7 over 35?
1 answer
7/35 = 0.2
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without calculating which of the following quotients can you determine will be positive.
A: -725 divide (-29) B: 1,001 divide
Top answer:
To determine if a quotient will be positive or negative, we need to consider the signs of the
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Without calculating, which of the following quotients can u determine will be positive?
657 divide (-23) -111 divide 37 -725
Top answer:
The quotient that can be determined to be positive without calculating is -725 divide (-29).
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Geometry B Semester Exam help please
i am on 13 right now 13. The length of the hypotenuse of a 30 -60 -90 triangle is 11 what is
Top answer:
the sides are in the ratio 1:√3:2 so if the hypotenuse is 11, the sides are 11/2, 11/2 √3, 11
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Which of the following should be done to both sides of the equation −6x=48 to solve the value of x ?(1 point)
Responses divide
Top answer:
divide by −6
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Which of the following should be done to both sides of the equation −6x=48 to solve the value of x ?(1 point) Responses divide
Top answer:
To solve the value of x in the equation −6x = 48, you should divide both sides of the equation by
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Which of the following should be done to both sides of the equation −6x=48 to solve the value of x?(1 point)
Responses divide
Top answer:
To solve for the value of x in the equation −6x=48, you should divide both sides of the equation
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Which of the following should be done to both sides of the equation −6x=48 to solve the value of x?(1 point)
Responses add 6
Top answer:
divide by −6
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Which of the following should be done to both sides of the equation −6x=48 to solve the value of x ?(1 point)
Responses divide
Top answer:
divide by -6
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3. What is the 2nd step in simplifying the expression 4² + 8 ÷ 2 ?(1 point)
Responses Square 4 Square 4 Divide 24 by 2 Divide
Top answer:
Divide 8 by 2
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Which of the following should be done to both sides of the equation −6x=48 to solve the value of x ?(1 point) Responses divide
Top answer:
To solve for the value of x in the equation −6x=48, you should divide both sides of the equation
Read more.
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