An object of mass m is dropped at t=0 from the roof of a building of hdight h. A wind blowing parallel to the face of the building exerts a constant force F on the object. At what time t does the object strike the ground? Express t in terms of g and h.

To determine the time it takes for the object to strike the ground, we need to consider the forces acting on it.

At any given time, the forces acting on the object are the gravitational force (mg) and the force exerted by the wind (F). Since the wind is blowing parallel to the face of the building, it doesn't affect the object's vertical motion, only its horizontal motion. Therefore, we can focus solely on the gravitational force.

We know that the gravitational force causes the object to accelerate downward at a rate of g (acceleration due to gravity). Using this information, we can use the kinematic equation for vertical motion:

h = (1/2)gt^2

Where:
h = height of the building
g = acceleration due to gravity
t = time taken for the object to strike the ground

Rearranging the equation, we have:

t = √(2h/g)

Therefore, the time it takes for the object to strike the ground is given by √(2h/g).