if 100j of heat energy is applied to a 25-g sample of mercury, by how many degrees will the temperature of the sample of mercury increase?
To determine the change in temperature, we can use the specific heat capacity formula:
q = m * c * ΔT
Where:
q = heat energy applied (in Joules)
m = mass of the sample (in grams)
c = specific heat capacity of the substance (in J/g°C)
ΔT = change in temperature (in °C)
Given:
q = 100 J
m = 25 g
c (specific heat capacity of mercury) = 0.14 J/g°C
Rearranging the equation, we find:
ΔT = q / (m * c)
Substituting the values, we have:
ΔT = 100 J / (25 g * 0.14 J/g°C)
= 100 J / 3.5 g°C
= 28.57 °C
Therefore, the temperature of the sample of mercury will increase by approximately 28.57 °C.
To find the increase in temperature of the sample of mercury, we can use the formula:
Q = mcΔT
Where:
Q is the heat energy applied to the sample
m is the mass of the sample
c is the specific heat capacity of the substance
ΔT is the change in temperature
In this case, the heat energy applied to the sample (Q) is 100 joules, the mass of the sample (m) is 25 grams, and the specific heat capacity of mercury (c) is 0.14 J/g°C.
First, we need to convert the mass of the sample from grams to kilograms, as the specific heat capacity is given in J/g°C:
25 grams = 0.025 kilograms
Now, we can rearrange the formula to solve for the change in temperature (ΔT):
ΔT = Q / (mc)
Substituting the given values:
ΔT = 100 J / (0.025 kg * 0.14 J/g°C)
ΔT = 100 J / 0.0035 J/°C
ΔT ≈ 28.57 °C
Therefore, the temperature of the sample of mercury will increase by approximately 28.57 degrees Celsius when 100J of heat energy is applied.
100 = mass Hg x seicific heat x delta T.
Solve for delta T.