Problem 22.2
2*10^ 13 electrons flow through a transistor in 1.0 ms.
Part A -
What is the current through the transistor?
Express your answer using two significant figures.
in mA
To find the current through the transistor, we need to use the formula:
current (I) = charge (Q) / time (t)
In this case, the charge is given as 2 * 10^13 electrons, and the time is given as 1.0 ms.
First, we need to convert the charge from electrons to units of coulombs since current is measured in amperes (A), which is coulombs per second (C/s).
1 electron has a charge of 1.6 * 10^-19 C.
So, to convert 2 * 10^13 electrons to coulombs:
charge (Q) = (2 * 10^13 electrons) * (1.6 * 10^-19 C/electron)
Next, we need to convert the time from milliseconds (ms) to seconds (s).
1 ms = 1 x 10^-3 s.
Now, we can substitute these values into the formula and calculate the current:
current (I) = charge (Q) / time (t)
= [(2 * 10^13 electrons) * (1.6 * 10^-19 C/electron)] / (1 x 10^-3 s)
Calculate the numerical value of the expression and express it using two significant figures. Then, convert the result to milliamperes (mA) by multiplying by 1000 since 1 A = 1000 mA.