abe left his house at 10:14 and goes north 14.0 kilometers to school then and south 70.6 kilometers to the candy store,arriving at 10:57.what are his displacement,total distance,average velocity?
To find Abe's displacement, total distance, and average velocity, we need to break down the given information. Let's start with the given data:
1. Abe goes north 14.0 kilometers to school.
2. Abe then travels south 70.6 kilometers to the candy store.
3. The time it takes for the entire trip is from 10:14 to 10:57.
Now, let's calculate each value step by step:
1. Displacement:
Displacement refers to the shortest straight-line path from the starting point to the ending point. In this case, Abe went north and then south, meaning his starting and ending points are the same. Therefore, his displacement is 0 kilometers.
2. Total distance:
To calculate the total distance, we need to find the sum of the distances traveled. Abe traveled 14.0 kilometers north to school and then 70.6 kilometers south to the candy store. Adding these distances gives us a total distance of 14.0 + 70.6 = 84.6 kilometers.
3. Average velocity:
Average velocity is calculated by dividing the displacement by the time it took to cover that distance. Since Abe's displacement is zero (he ended up where he started), his average velocity is also zero. This means he had no net displacement per unit of time.
In summary:
- Displacement = 0 kilometers
- Total distance = 84.6 kilometers
- Average velocity = 0 km/h (no displacement over time)