An object measures 12 x 3 x 2.5 cm and has a density of 0.6 g/cm3. When it
is placed in water, what is the volume of the part of the object that is above
the surface of the water?
To find the volume of the part of the object that is above the surface of the water, we first need to determine the total volume of the object and then subtract the volume of the part submerged in water.
The total volume of the object can be calculated by multiplying its length, width, and height. In this case, the object measures 12 x 3 x 2.5 cm, so its total volume is:
Volume = length x width x height
Volume = 12 cm x 3 cm x 2.5 cm
Volume = 90 cm³
Now, to determine the volume of the part submerged in water, we can use the concept of density. Density is defined as mass divided by volume. In this case, the object has a density of 0.6 g/cm³.
Since density = mass / volume, we can rearrange the formula to find volume: volume = mass / density.
Since we only have the density, we need to find the mass of the object. This can be calculated by multiplying the density of the object by its volume.
Mass = density x volume
Mass = 0.6 g/cm³ x 90 cm³
Mass = 54 grams
Now that we have the mass, we can determine the volume of the part submerged in water using the formula volume = mass / density:
Volume of submerged part = mass / density
Volume of submerged part = 54 g / 0.6 g/cm³
Volume of submerged part = 90 cm³
Finally, to find the volume of the part of the object above the surface of the water, we subtract the volume of the submerged part from the total volume:
Volume above water = Total volume - Volume of submerged part
Volume above water = 90 cm³ - 90 cm³
Volume above water = 0 cm³
Therefore, the volume of the part of the object that is above the surface of the water is 0 cm³.