Write the balanced, complete, and net ionic equations for each precipitation reaction.
1) AgNO_3 + CoCl_2 --->
BE: AgNO_3(aq) + CoCl_2(aq) ---> AgCl_2 (aq) + Co(NO_3)(aq)
CIE: Since the balanced equation is all (aq) there is no reaction so no complete or net equation.
2) AgNO_3 + Na_2CrO_4 --->
BE: AgNO_3 (aq) + Na_2CrO_4 (s) ---> AgCrO_4 (s) + Na_2(NO_3) (aq)
CIE: Ag^+ (s) + NO_3- (aq) + Na_2^+ (s) + CrO_4 ^2- (s) ---> AgCrO_4 (S) + Na_2^+ (s) + (NO_3)^- (aq)
NIE: Ag^+ (s) + CrO_4^2- (s) ---> AgCrO_4^2- (s)
Are these answers correct. Thank you for your help!!!
1) 2AgNO3(aq) + CoCl2(aq)==> 2AgCl(s) + Co(NO3)2 is the balanced molecular equation.
The balanced net ionic equation is (using the smallest set of numbers)
Ag^+(aq) + Cl^-(aq) ==> AgCl(s)
You need to know the solubility rules to do these. Here is a simplified set of same.
http://www.files.chem.vt.edu/RVGS/ACT/notes/solubility_rules.html
thank you for your help. For number 1 is there a complete ionic equation?
The balanced equations for the given precipitation reactions are correct. Here is a summary:
1) AgNO3 + CoCl2 -> AgCl + Co(NO3)2
- Balanced Equation: AgNO3(aq) + CoCl2(aq) -> AgCl(s) + Co(NO3)2(aq)
2) AgNO3 + Na2CrO4 -> AgCrO4 + NaNO3
- Balanced Equation: AgNO3(aq) + Na2CrO4(aq) -> AgCrO4(s) + NaNO3(aq)
For the net ionic equation, you correctly identified the ions that are involved in the reaction and canceled out the spectator ions. So, the net ionic equation for the second reaction is:
Ag+(aq) + CrO4^2-(aq) -> AgCrO4(s)
Great job!