
posted by MathMate
Respond to this Question
Similar Questions

CALCULUS  need help!
Determine the limit of the trigonometric function (if it exists). 1. lim sin x / 5x (x > 0) 2. lim tan^2x / x (x >0) 3. lim cos x tan x / x (x > 0) 
Calculus, please check my answers!
1. Evaluate: lim x>infinity(x^47x+9)/(4+5x+x^3) 0 1/4 1 4 ***The limit does not exist. 2. Evaluate: lim x>infinity (2^x+x^3)/(x^2+3^x) 0 1 3/2 ***2/3 The limit does not exist. 3. lim x>0 (x^37x+9)/(4^x+x^3) 0 1/4 1 
Limits
Let lim f(x) =16 as x>4 and lim g(x) =8 as x>4 Use the limit rules to find lim [cos(pi*f(x)/g(x))] as x>4 
Calculus help, please!
1. Evaluate: lim x>infinity(x^47x+9)/(4+5x+x^3) 0 1/4 1 4 The limit does not exist. 2. Evaluate: lim x>infinity (2^x+x^3)/(x^2+3^x) 0 1 3/2 2/3 The limit does not exist. 3. lim x>0 (x^37x+9)/(4^x+x^3) 0 1/4 1 9 The 
Calculus
yes! tnk u ok? It's actually (x>0.) Find the limit of cot(x)csc(x) as x approached 0? Lim [cot(x)  csc (x)] ..x>0 = Lim [(cos x 1)/sin x] ..x>0 Use L'Hopital's rule and take the ratio of the derivatives: Lim (sin 
Calculus. Limits. Check my answers, please! :)
4. lim (tanx)= x>pi/3 (sqrt3) 1 (sqrt3) ***1 The limit does not exist. 5. lim x= x>2 2 ***2 0 1 The limit does not exist. 6. lim [[x]]= x>9/2 (Remember that [[x]] represents the greatest integer function of x.) 
calculus
calculate the lim as x> pi (cos(x)+1)/(xpi) using the special limit lim x>0 sinx/x 
calc
need to find: lim as x > 0 of 4(e^2x  1) / (e^x 1) Try splitting the limit for the numerator and denominator lim lim x>0 4(e^2x1) (4)x>0 (e^2x1) ______________ = ________________ lim lim x>0 e^X1 x>0 e^x1 
calculus
The limit represents the derivative of some function f at some number a. Select an appropriate f(x) and a. lim (cos(pi+h)+1)/h h>0 answers are f(x) = tan(x), a = pi f(x) = cos(x), a = pi/4 f(x) = cos(x), a = pi f(x) = sin(x), 
math
the limit of cuberoot((3x^3+5x+2)/(x^21)) as x approaches 3 is the problem. how could (3x^3+5x+2) so it would be factored out with denominator? thanks! If you read the answer I gave for the previous question, then you can take