calculate the moles of compound in 0.540 grams of ammonium Bromide
To calculate the moles of a compound, we need to use its molar mass. The molar mass is the mass of one mole of a substance, which is equal to the sum of the atomic masses of all the elements in the compound.
In this case, the compound is ammonium bromide (NH4Br). To calculate its molar mass, we need to find the individual atomic masses of nitrogen (N), hydrogen (H), and bromine (Br).
The atomic mass of nitrogen (N) is approximately 14.01 grams/mol.
The atomic mass of hydrogen (H) is approximately 1.01 grams/mol.
The atomic mass of bromine (Br) is approximately 79.90 grams/mol.
Now, let's calculate the molar mass of ammonium bromide (NH4Br):
1 nitrogen (N) atom = 1 x 14.01 grams/mol = 14.01 grams/mol
4 hydrogen (H) atoms = 4 x 1.01 grams/mol = 4.04 grams/mol
1 bromine (Br) atom = 1 x 79.90 grams/mol = 79.90 grams/mol
Adding all these masses together, we get:
Molar mass of NH4Br = 14.01 + 4.04 + 79.90 = 98.95 grams/mol
Now we can calculate the moles of ammonium bromide in 0.540 grams using the following formula:
moles = mass / molar mass
moles = 0.540 grams / 98.95 grams/mol
moles ≈ 0.00546 mol
Therefore, there are approximately 0.00546 moles of ammonium bromide in 0.540 grams of the compound.