a recycling company collected d kg of waste paper in february&2400 kg of waste paper in march.The amount of waste paper collected in both february&march was 3 times that of the amount collected in january in terms of d.
(a) Find the amount of waste paper collected in january in terms of d.
(b) If the recycling company collected 4500kg of paper in february, what was the amount of waste paper collected in january? Help me pls !
X-kgs collected in Jan.
d-kg collected in Feb.
2400kg collected in Mar.
a. 3x = d + 2400,
X = (d + 2400) / 3.
b. X = (4500 + 2400) / 3 = 2300kg Collected in Jan.
www.freerobux.com
Num 1 = 3 รท (d + 2400) kg
Num 2 = (4500 + 2400) / 3 = 2300kg
To solve this problem, we need to set up equations and use the information given. Let's start with part (a):
(a) Let's assume that the amount of waste paper collected in January is x kg. According to the given information, the amount of waste paper collected in both February and March is 3 times that of January in terms of d.
So, the amount of waste paper collected in February is 3x kg.
And the amount of waste paper collected in March is 3x kg.
We also know that in February, they collected 2400 kg of waste paper. Hence, we can set up the following equation:
3x = 2400
Now we can solve for x by dividing both sides of the equation by 3:
x = 2400 / 3
x = 800
So, the amount of waste paper collected in January, in terms of d, is 800 kg.
Now let's move on to part (b).
(b) We are given that the recycling company collected 4500 kg of waste paper in February. We can set up the following equation based on the information we have:
3x = 4500
We already know from part (a) that x is equal to 800. Substituting this in the equation:
3(800) = 4500
Now we can solve for 3x:
2400 = 4500
This equation is not true, which means our assumption from part (a) is wrong. Therefore, there may have been an error or inconsistency in the information given. Please double-check the problem statement and clarify the data provided to get an accurate solution.