how do you substitute these system of equations

1.y=-3x-3
y=3x-3

2.y=4x-6
y=x

thank you!

1. take the value of y from the first, and plug it into the second.

(-3x-3) = 3x-3
0 = 6x
x = 0
y = -3

2. do it the other way, since the second is so simple.
x = 4x-6
3x = 6
x=2
y=2

1.y=-3x-3

y=3x-3
try
-3 x - 3 = 3 x - 3
0 = 6 x
x = 0
then y = -3
=======================
2.y=4x-6
y=x
try
x = 4 x - 6
3 x = 6
x = 2
then
y = 2

To substitute equations, you need to solve one equation for a variable and then substitute that expression into the other equation. Let's go through each system of equations step by step.

1. First, we'll solve the first equation for 'y':
y = -3x - 3

2. Now, substitute this expression for 'y' in the second equation:
y = 3x - 3

Replace 'y' with '-3x - 3':
-3x - 3 = 3x - 3

3. Simplify and solve for 'x':
Add 3x to both sides of the equation:
-3 - 3 = 3x + 3x
-6 = 6x

Divide both sides by 6:
-6/6 = 6x/6
-1 = x

4. Substitute the value of 'x' back into any equation to find 'y':
Using the first equation:
y = -3x - 3
y = -3(-1) - 3
y = 3 - 3
y = 0

Therefore, the solution to the first system of equations is x = -1 and y = 0.

Now, let's move on to the second system of equations:

1. The equation is already solved for 'y':
y = 4x - 6

2. Substitute this expression for 'y' in the second equation:
y = x

Replace 'y' with '4x - 6':
4x - 6 = x

3. Simplify and solve for 'x':
Subtract 'x' from both sides of the equation:
4x - x - 6 = x - x
3x - 6 = 0

Add 6 to both sides of the equation:
3x - 6 + 6 = 0 + 6
3x = 6

Divide both sides by 3:
(3x)/3 = 6/3
x = 2

4. Substitute the value of 'x' back into any equation to find 'y':
Using the first equation:
y = 4x - 6
y = 4(2) - 6
y = 8 - 6
y = 2

Therefore, the solution to the second system of equations is x = 2 and y = 2.