# math

Amy bought some stationary from a bookstore. The total cost of 3 files A,B,C was \$5.60 more than the total cost of 4staples. A cost \$1.90 less than each of the other 2files. B cost \$4.20 more than each staple. Find the cost of C

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1. \$X = Cost of B.
\$X = Cost of C.
X -!.90 = Cost of A.

X - 4.20 = Cost of each staple.

X + X + (X-1.90) = 4(X-4.20) + 5.60,
3x - 1.90 = 4x-16.80 + 5.60,
3x - 4x = -16.80 + 5.60 + 1.90 = -9.30,
-x = -9.30,

X = \$9.30. = Cost of B.
X = \$9.30 = Cost of C.
X-1.90 = 9.30 - 1.90 = \$7.40=Cost of A.

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