Maria is three times as old as her brother.In 4 years,Maria will be twice as old as he will be then.How old is Maria's brother now?

Help need equation

Let x = maria's age and y = her brother's.

x = 3y

(x+4) = 2(y+4)

Substitute 3y for x in second equation and solve for y. Insert that value into the first equation and solve for x. Check by inserting both values into the second equation.

6=24

y=4

x=12

Lindana

Waste quedtion

To solve this problem, you can use algebraic equations. Let's assume Maria's brother's age is represented by "x" years.

According to the given information, Maria's age is three times her brother's age, so Maria's age is 3x years.

In four years, Maria will be twice as old as her brother will be then. So, in four years, Maria's age will be (3x + 4) years, and her brother's age will be (x + 4) years.

Based on the statement, we can write the following equation: (3x + 4) = 2(x + 4).

Now, let's solve this equation to find the value of x:

3x + 4 = 2x + 8
3x - 2x = 8 - 4
x = 4

Therefore, Maria's brother's age, represented as "x", is 4 years old.