a 2kg block of iron is given 10kj of energy and its temperature rises by 10c. what is the specific heat capacity of iron?
q = mass x specific heat x delta T.
Solve for specific heat.
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To find the specific heat capacity of iron, we can use the formula:
Q = mcΔT
Where:
Q is the energy supplied (in Joules),
m is the mass of the object (in kg),
c is the specific heat capacity (in J/kg°C), and
ΔT is the change in temperature (in °C).
In this case, the energy supplied (Q) is 10 kJ, which is equal to 10,000 J. The mass of the iron block (m) is 2 kg, and the change in temperature (ΔT) is 10°C.
Plugging the given values into the formula, we get:
10,000 J = 2 kg * c * 10°C
Now we can solve for the specific heat capacity (c):
c = 10,000 J / (2 kg * 10°C)
c = 500 J/kg°C
Therefore, the specific heat capacity of iron is 500 J/kg°C.
To calculate the specific heat capacity of iron, you can use the formula:
Q = mcΔT
Where:
Q = Heat energy (in joules)
m = Mass of the object (in kg)
c = Specific heat capacity of the material (in J/kg·°C)
ΔT = Change in temperature (in °C)
In this case, the mass of the iron block (m) is 2 kg, the heat energy given to the block (Q) is 10 kJ (which is 10,000 J), and the change in temperature (ΔT) is 10°C.
Now, substitute the known values into the formula and solve for c:
10,000 J = (2 kg) × c × 10°C
Divide both sides of the equation by (2 kg × 10°C) to solve for c:
c = 10,000 J / (2 kg × 10°C)
c = 500 J/kg·°C
Therefore, the specific heat capacity of iron is 500 J/kg·°C.