An air track glider, 8.0 cm long, blocks light as it goes through a photocell gate. The glider is released from rest on a frictionless inclined track and the gate is positioned so that the glider has travelled 96 cm when it is in the middle of the gate. The timer gives a reading of 333 m/s for the glider to pass through this gate. Friction is negligible. What is the acceleration (assumed constant) of the glider along the track?

To find the acceleration of the glider along the track, we can use the kinematic equation:

v^2 = u^2 + 2as

Where:
v = final velocity of the glider
u = initial velocity of the glider
a = acceleration
s = distance traveled

We want to find the acceleration, so we need to rearrange the equation to solve for a:

a = (v^2 - u^2) / (2s)

Given information:
The initial velocity, u, is 0 m/s because the glider is released from rest.
The final velocity, v, is given as 333 m/s.
The distance traveled, s, is 96 cm, which is equal to 0.96 m.

Now we can substitute the values into the equation and calculate the acceleration:

a = (333^2 - 0^2) / (2 * 0.96)
a = 110889 / 1.92
a ≈ 57736.46 m/s^2

The acceleration of the glider along the track is approximately 57736.46 m/s^2.