A 500.0 ml sodium iodide (Nai) solution contains 31.7g of Nal. what is the molar concentration of the solution?
moles NaI = grams/molar mass.
Solve for moles.
M = moles/L
Substitute and solve for M.
To find the molar concentration of the solution, we need to calculate the number of moles of sodium iodide (NaI) present in the solution.
The formula to calculate the number of moles is:
Moles = Mass / Molar mass
First, we need to determine the molar mass of sodium iodide (NaI). Sodium (Na) has an atomic mass of 22.99 g/mol, and iodine (I) has an atomic mass of 126.90 g/mol. Since sodium iodide (NaI) has one atom of sodium and one atom of iodine, the molar mass of NaI is:
Molar mass (NaI) = Atomic mass (Na) + Atomic mass (I)
Molar mass (NaI) = 22.99 g/mol + 126.90 g/mol
Molar mass (NaI) = 149.89 g/mol
Next, we can calculate the number of moles of NaI:
Moles (NaI) = Mass (NaI) / Molar mass (NaI)
Moles (NaI) = 31.7 g / 149.89 g/mol
Moles (NaI) = 0.2113 mol
Finally, we need to calculate the molar concentration (mol/L) of the solution by dividing the number of moles by the volume of the solution in liters:
Molar concentration = Moles (NaI) / Volume (L)
Molar concentration = 0.2113 mol / 0.500 L
Molar concentration = 0.4226 mol/L
Therefore, the molar concentration of the sodium iodide (NaI) solution is 0.4226 mol/L.