physics

a student drops a ball from a window 3.5m above the sidewalk. the ball accelerates at 9.80m/s^2. How fast is it moving when it hits the sidewalk.

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  1. Vf^2 = Vo^2 + 2g*d,
    Vf^2 = 0 + 19.6*3.5 = 68.6,
    Vf = 8.28m/s.

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  2. Vf^2= Vi^2 + 2ad
    Vf^2= 2(-9.80)(3.5)
    Vf^2= -68.6
    (square root Vf^2 and drop the - on 68.6 and square root it)
    Vf= 8.3 m/s down
    (answer is rounded up to 2 sig figs)

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