(time given is the total time in the air)
During a baseball game, a batter hits a high pop-up.
If the ball remains in the air for 4.5 s, how high does it rise? The acceleration of gravity is 9.8 m/s^2.
Answer in units of m
To determine the height the ball rises, we can make use of the kinematic equation:
h = v0t + (1/2)gt^2
Where:
h is the height
v0 is the initial vertical velocity (which is 0 since the ball starts from rest)
t is the time of flight
g is the acceleration due to gravity (9.8 m/s^2)
Given that the ball remains in the air for 4.5 seconds, we can substitute the values into the equation:
h = (0)(4.5) + (1/2)(9.8)(4.5)^2
Simplifying this equation will give us the height the ball rises:
h = 0 + (1/2)(9.8)(20.25)
h = 0 + 99.45
h = 99.45 m
Therefore, the ball rises approximately 99.45 meters.