math

The hypotenuse of a right triangle measures 10m. One leg of the triangle is 2m longer then the other. Find the lengths of the legs.

How would you solve this equation?

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  1. First of all, you have to write the equation. Call the shorter leg of the triangle x.

    x^2 + (x+2)^2 = 10^2 = 100

    2x^2 + 4x + 4 = 100
    x^2 + 2x -48 = 0
    (x+8)(x-6) = 0

    Solve for x etc

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  2. thank you :)

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