Question

What is the approximate volume of 0.095 M HCl needed to neutralize 0.25g of sodium carbonate. Hint: Write a balanced equation first.

Answer 1

Na2CO3 + 2HCl ==> CO2 + H2O + 2NaCl

Here is a worked example of a stoichiometry problem. Remember moles = M x L.
http://www.jiskha.com/science/chemistry/stoichiometry.html