A plane is traveling at 300 m/s drops a bomb which hits it target 10 sec later. How high was the plane flying?
How was 9.8 gotten
9.8 is a constant. It's d value of gravity
To find the height of the plane, we can use the formula:
height = initial velocity * time + (1/2) * acceleration * time^2
In this case, the initial velocity is 300 m/s, the time is 10 seconds, and the acceleration is the acceleration due to gravity, which is approximately 9.8 m/s^2.
Plugging in the values:
height = 300 * 10 + (1/2) * 9.8 * 10^2
= 3000 + 490
= 3490 meters
Therefore, the plane was flying at a height of 3490 meters.
S=Ut+1/2at²
S=0×10+0.5×9.8×10²
S=0+4.9×100
S=490m