Hi! Ijust have one question that I don't know how to do:
(a)How long will it take a freely falling body to acquire a speed of 58.8 m/s^2.(b) How far will it have fallen during that time?
Sure! I can help you with that.
To find the time it takes for a body to acquire a certain speed during free fall, you can use the kinematic equation:
v = u + gt
Where:
v is the final velocity (58.8 m/s in this case)
u is the initial velocity (assumed to be 0 m/s for a freely falling body)
g is the acceleration due to gravity (approximately 9.8 m/s^2 on Earth)
t is the time taken
To solve for t, rearrange the equation:
t = (v - u) / g
Substituting the given values into the equation:
t = (58.8 m/s - 0 m/s) / 9.8 m/s^2
t = 6 seconds
So, it will take 6 seconds for the body to acquire a speed of 58.8 m/s during free fall.
Next, to find the distance the body will have fallen during that time, you can use another kinematic equation:
s = ut + (1/2)gt^2
Where:
s is the distance
u is the initial velocity (0 m/s)
t is the time (6 seconds)
g is the acceleration due to gravity (9.8 m/s^2)
Substituting the given values into the equation:
s = (0 m/s) * 6 seconds + (1/2) * (9.8 m/s^2) * (6 seconds)^2
s = 0 + 0.5 * 9.8 * 36
s = 0 + 176.4
s = 176.4 meters
So, the body will have fallen approximately 176.4 meters during the 6 seconds of free fall.